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Determine whether the differential equation is linear.

$ y' + x \sqrt y = x^2 $

$$(1), y^{\prime}+P(x) y=Q(x)$$

Differential Equations

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we know there's a very specific form for First Order Lanier Differential Equation. The form is Do I over D axe derivative plus p of x times. Why is Q Becks, this is the formula listed in textbooks. Now, in this case, we have a square root of why term that you could see in the problem. So because of this term, this doesn't follow the formula for our first order when your differential equation. Therefore, we know that it is not a linear differential equation.